WebOct 17, 2024 · In order to achieve this, we store the maximum of (N / (i * 10)) * i + (N % i) where i ranges from [1, 10l – 1] where l denotes the number of digits of the current value of N. Consider this maximum as the current value of N and proceed to the next iteration and repeat the above step. WebDec 29, 2024 · using namespace std; const int MAX = 10; bool isDigit (char ch) { if (ch >= '0' && ch <= '9') return true; return false; } bool allDigits (string str, int len) { bool present [MAX] = { false }; for (int i = 0; i < len; i++) { if (isDigit (str [i])) { int digit = str [i] - '0'; present [digit] = true; } } for (int i = 0; i < MAX; i++) {
Largest number possible after removal of K digits
WebJan 31, 2024 · Its solution is simple i.e. Start traversing the string and perform two operations: 1) If a numeric value is present at the current index then convert it into an integer num = num*10 + (str [i]-'0') 2) Otherwise, update the maximum value and reset num = 0. Return the maximum value at the last. C++ Java Python3 C# PHP Javascript WebApr 11, 2024 · The idea is simple, we write a function that counts occurrences of a given digit in a given integer. Then we count all digits from 0 to 9 in given integer. We keep updating maximum count whenever count becomes more or same as previous count. Below is the implementation. Implementation: C++ Java Python3 C# PHP Javascript … heating pad teddy bear for kids
Find the most frequent digit without using array/string
WebFeb 10, 2024 · template void findMax (std::vector& arrayVector) { if (arrayVector.size () == 0) //stop condition return; int max = *std::max_element (arrayVector.begin (), arrayVector.end ()); std::cout << "Max value: "<< max << std::endl; arrayVector.erase (arrayVector.end () - 1); //last element being deleted in every recursion findMax … WebSep 16, 2024 · Write a function: def solution (A): such that, given an array A consisting of N integers, it returns the maximum among all one-digit integers. For example, given array A as follows: [-6, -91, 1011, -100, 84, -22, 0, 1, 473] the function should return 1. Assume that: N is an integer within the range [1...1,000] WebFeb 20, 2024 · Run a loop from the current index to the end of the array If the ith digit is equal to the maximum element Swap the ith and element at the current index and check if the string is now maximum and update the maximum string. Call the function recursively with parameters: string and k. Now again swap back the ith and element at the current … movie theaters in richland